Question

A parallel plate capacitor is connected to a battery that has a potential difference of 200 V. Once charged, each plate on the capacitor holds a charge of 5.0 × 10-9C. What is the capacitance of the parallel plate capacitor?

A. 2.0 × 10-6 F

B. 2.5 × 10-11 F

C. 5.0 × 10-11 F

D. 1.0 × 10-6 F

Answer 1

Correct Answer: B option

Potential Difference = V = 200 V
Charge on the plate = Q = $5.0*10^{-9}$ C
Capacitance = C

Q, C and V for a parallel plate capacitor are related as:

Q = CV
⇒
C = Q/V

Using the values in the formula, we get:

$C= \frac{5*10^{-9} }{200}=2.5*10^{-11}$ F

Therefore, B option is the correct answer.