Question

Which of the following equations has only one solution?
x2 - 8x + 16 = 0 x(x - 1) = 8 x2 = 16

Answer 1

If your choices are the following:
A. x2 - 8x + 16 = 0
B. x(x - 1) = 8
C. x2 = 16

The answer is letter A. The linear equation, x2 - 8x + 16 = 0, will give you one solution only.

Answer 2

Correct Answer is: $x^{2} -8x+16=0$

The expression can be written as a perfect square, resulting in only 1 solution as shown below:

$x^{2} -2(x)(4)+(4)^{2} \\ \\ (x-4)^{2}=0 \\ \\ x-4=0 \\ \\ x=4$