Respuesta :
Let's take this step by step. First, let's find the area of the triangle:
[tex]A_t = \frac{1}{2}bh = \frac{1}{2}(13-7)(4+4)= \frac{1}{2}(6)(8) = 24cm^2 [/tex]
Small rectangle:
[tex]A = lw = 7*4 = 28cm^2[/tex]
Big rectangle:
[tex]A = lw = 10*4 = 40 cm^2[/tex]
Let's add all the areas up:
[tex]A_T = 24+28+40 = 92cm^2[/tex]
So, your answer is: The area of this figure is 92 cm².
[tex]A_t = \frac{1}{2}bh = \frac{1}{2}(13-7)(4+4)= \frac{1}{2}(6)(8) = 24cm^2 [/tex]
Small rectangle:
[tex]A = lw = 7*4 = 28cm^2[/tex]
Big rectangle:
[tex]A = lw = 10*4 = 40 cm^2[/tex]
Let's add all the areas up:
[tex]A_T = 24+28+40 = 92cm^2[/tex]
So, your answer is: The area of this figure is 92 cm².
Dce- 28
Fca-40
Triangle-12
Dce-4•7
Fca-10•4
Triangle-1/2(3)(8)
Fca-40
Triangle-12
Dce-4•7
Fca-10•4
Triangle-1/2(3)(8)