Question

A construction company needs 5 1/6 tons of dirt from a construction site. They can remove 5/9 tons of dirt each hour. What is the total number of hours it will take to remove the dirt ?

Answer 1

One hour = 5/6 tons of dirt.

Number of hour needed to remove 5 1/6 tons of dirt:

$5 \dfrac{1}{6} \div \dfrac{5}{6}$

Write in improper fraction:

$=\dfrac{31}{6} \div \dfrac{5}{6}$

Change the divide fraction to multiplication fraction:

$=\dfrac{31}{6} \times \dfrac{6}{5}$

Combine into single fraction:

$=\dfrac{31}{5}$

$=6\dfrac{1}{5} \text { hours }$

Answer 2

in 1 hr they can remove 5/6 amount of dirt