PLEASE!!!!Solving for Measures of Right Triangles:
Use the diagram to complete the statements. The measure of angle L is °. The trigonometric ratio that uses ∠M and LN to solve for NM is . The length of NM, to the nearest tenth, is approximately .

PLEASESolving for Measures of Right Triangles Use the diagram to complete the statements The measure of angle L is The trigonometric ratio that uses M and LN to class=

Respuesta :

Angle L = 70
The ratio is = tangent
The length of NM is = 57.7

The measure of angle L is [tex]70^\circ[/tex], the trigonometric ratio that uses [tex]\rm \angle M[/tex] and LN to solve for NM is a tangent and the length of NM is 57.70 units.

Given :

  • Triangle LMN.
  • [tex]\rm \angle M = 20^\circ[/tex]
  • [tex]\rm \angle N = 90^\circ[/tex]
  • Length of NL = 21 units.

Solution :

We know that the sum of all three interior angles of a triangle is [tex]180^\circ[/tex].

[tex]\rm \angle M +\angle N + \angle L = 180^\circ[/tex]

[tex]\rm 20^\circ + 90^\circ + \angle L = 180^\circ[/tex]

[tex]\rm \angle L = 180^\circ - 110^\circ[/tex]

[tex]\rm \angle L = 70^\circ[/tex]

It is given that the triangle LMN is a right angle triangle so NM is perpendicular, LM is hypotenuse and LN is base.

From trignometry function we know that the formula of [tex]\rm tan\theta[/tex] is given by:

[tex]\rm tan \theta = \dfrac{Perpendicular}{Base}[/tex]

[tex]\rm tan (L) = \dfrac{ MN }{21}[/tex]

[tex]\rm 2.7474\times 21 = MN[/tex]

MN = 57.70 units

From trignometry function we know that the formula of [tex]\rm sin\theta[/tex] is given by:

[tex]\rm sin \theta = \dfrac{Perpendicular}{Hypotenuse}[/tex]

[tex]\rm sin(70^\circ) = \dfrac{57.70}{LM}[/tex]

LM = 61.40 units

The trigonometric ratio that uses [tex]\rm \angle M[/tex] and LN to solve for NM is a tangent.

For more information, refer the link given below

https://brainly.com/question/19731462

ACCESS MORE