The measure of angle L is [tex]70^\circ[/tex], the trigonometric ratio that uses [tex]\rm \angle M[/tex] and LN to solve for NM is a tangent and the length of NM is 57.70 units.
Given :
- [tex]\rm \angle M = 20^\circ[/tex]
- [tex]\rm \angle N = 90^\circ[/tex]
Solution :
We know that the sum of all three interior angles of a triangle is [tex]180^\circ[/tex].
[tex]\rm \angle M +\angle N + \angle L = 180^\circ[/tex]
[tex]\rm 20^\circ + 90^\circ + \angle L = 180^\circ[/tex]
[tex]\rm \angle L = 180^\circ - 110^\circ[/tex]
[tex]\rm \angle L = 70^\circ[/tex]
It is given that the triangle LMN is a right angle triangle so NM is perpendicular, LM is hypotenuse and LN is base.
From trignometry function we know that the formula of [tex]\rm tan\theta[/tex] is given by:
[tex]\rm tan \theta = \dfrac{Perpendicular}{Base}[/tex]
[tex]\rm tan (L) = \dfrac{ MN }{21}[/tex]
[tex]\rm 2.7474\times 21 = MN[/tex]
MN = 57.70 units
From trignometry function we know that the formula of [tex]\rm sin\theta[/tex] is given by:
[tex]\rm sin \theta = \dfrac{Perpendicular}{Hypotenuse}[/tex]
[tex]\rm sin(70^\circ) = \dfrac{57.70}{LM}[/tex]
LM = 61.40 units
The trigonometric ratio that uses [tex]\rm \angle M[/tex] and LN to solve for NM is a tangent.
For more information, refer the link given below
https://brainly.com/question/19731462