Respuesta :
The smallest y-intercept would be of the first function. (0, 6)
Since Blake is starting with $6, that is the y-intercept.
For the function, f(x) = 4^x + 3, the y-intercept is 7.
For the last function, f(x) = 10(2)^x , the y-intercept is 10.
6 is the lowest of 6, 7, and 10.
Since Blake is starting with $6, that is the y-intercept.
For the function, f(x) = 4^x + 3, the y-intercept is 7.
For the last function, f(x) = 10(2)^x , the y-intercept is 10.
6 is the lowest of 6, 7, and 10.
Answer:
The smallest y-intercept is 4 whose function is h(x)
C is correct.
Step-by-step explanation:
Given four functions, which one will have the smallest y-intercept
For function f(x)
Blake is tracking his savings account with an interest rate of 5% and a original deposit of $6.
[tex]y=6(1+0.05)^x[/tex]
[tex]y=6(1.05)^x[/tex]
[tex]f(x)=6(1.05)^x[/tex]
where, y is final amount and x is number of period.
y-intercept of f(x). Put x=0
[tex]f(0)=6[/tex]
y-intercept: (0,6)
For function g(x)
x : 0 1 2
g(x) : 6 8 12
Using table, y-intercept of g(x)
g(0)=6
y-intercept: (0,6)
For function h(x)
[tex]h(x)=4^x+3[/tex]
For y-intercept of h(x). Put x=0
[tex]h(0)=4^0+3=4[/tex]
y-intercept: (0,4)
For function j(x)
[tex]j(x)=10(2)^x[/tex]
For y-intercept of j(x). Put x=0
[tex]j(0)=10(2)^0=10[/tex]
y-intercept: (0,10)
Function : f(x) g(x) h(x) j(x)
y-intercept : 6 6 4 10
Hence, The smallest y-intercept is 4 whose function is h(x)