We have the following function:
f (x) = x ^ 2 + 1
We apply the transformation f (x + 3) +9:
g (x) = (x + 3) ^ 2 + 1 + 9
Rewriting we have:
g (x) = (x + 3) * (x + 3) + 1 + 9
g (x) = (x ^ 2 + 3x + 3x + 9) + 1 + 9
g (x) = (x ^ 2 + 6x + 9) + 1 + 9
g (x) = x ^ 2 + 6x + 9 + 1 + 9
g (x) = x ^ 2 + 6x + 19
Answer:
the resulting function if the transformation f (x + 3) +9 is applied on the function f (x) = x ^ 2 + 1 is:
c) x ^ 2 + 6x + 19