Question

A farm is to be built in the shape of Quadrilateral ABCD, as shown below.
All four sides are equal.
A rhombus ABCD is shown with diagonal AC equal to 12.6 feet and diagonal BD equal to 10.4 feet. What is the area of the farm?

32.76 square feet
46 square feet
65.52 square feet
92 square feet

Answer 1

When we have diagonals $d_1$ and $d_2$ of a rhombus its area is:

$A=\dfrac{1}{2}\cdot d_1\cdot d_2=\dfrac{1}{2}\cdot |AC|\cdot |BD|=\dfrac{1}{2}\cdot12.6\cdot10.4=\dfrac{1}{2}\cdot 131.04=\\\\\\=\boxed{65.52\text{ feet}^2}$

Answer C)

Answer 2

The area of the farm that looks like a rhombus is 65.52 ft²

How to find area of a rhombus?

The farm is shaped like a rhombus.

Therefore,

area of a rhombus = pq / 2

where

• p and q are the diagonal length

Therefore,

p = 12.6 ft

q = 10.4 ft

Hence,

area of the farm = 10.4 × 12.6 / 2 = 131.04 / 2 = 65.52 ft²

learn more on area here: https://brainly.com/question/26170459

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