Two cyclists, 132 mi apart, start riding toward each other at the same time. one cycles twice as fast as the other. if they meet 4 h later, at what average speed is each cyclist traveling?
If one cyclist is twice as fast as the the other cyclist ⇒ one cyclist would have covered 1/3 of the journey and the other 2/3
132 ÷ 3 = 44. 44 x 2 = 88. The slower cyclist covered 44 miles whereas the faster cyclist covered 88 miles.
They met 4 hours later, Speed of the slower cyclist = 44/4 = 11 miles/hour Speed of the faster cyclist = 88/4 = 22 miles/hour
-------------------------------------------------------------------------- Answer: The average speed of the slower cyclist is 11 miles/hour and the average speed of the faster cyclist is 22 miles/hour. --------------------------------------------------------------------------
