Respuesta :

Answer:

\frac{1}{8} (sin 5+sin 3)

Step-by-step explanation:

step 1:-

average value of given function =[tex]\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx[/tex]

[[tex]\frac{1}{8}(sin 5-(sin(-3)) \\\\\frac{1}{8} (sin 5+sin 3)[/tex]

Final answer:-

\frac{1}{8} (sin 5+sin 3)

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