Respuesta :
General Idea:
[tex] Sin (A) = Cos(90 - A) [/tex]
Given:
[tex] sin(x+11)^{\circ}=cos(2x+22)^{\circ} \Rightarrow 1^{st} \; equation [/tex]
Applying the concept:
Using the given rule we can rewrite the left hand side of the equation as below:
[tex] Sin(x+11)=cos(90 - (x+11))=cos(90 -x-11)=cos(79-x) [/tex]
Substituting the above result in 1st equation, we get...
[tex] cos(79-x)=cos(2x+22)\\\\Equating \; angles\; we get...\\\\79-x=2x+22\\Adding \; x \; on \; both \; sides \; and \; subtracting \; 22 \; on \; both \; sides, \; we \; get...\\\\79 -22 = 2x + x\\ Combining \; like \; terms \\\\3x = 57\\ Dividing \; by \; 3 \; on \; both \; sides \\\\ \frac{3x}{3} = \frac{57}{3} \\Simplifying \; fraction \; on \; both \; sides\\\\x=19 [/tex]
Conclusion:
The value of x which will make the equation sin(x+11)°=cos(2x+22)° TRUE is 19 degrees.