Respuesta :
Answer:
[tex]x=\frac{536}{165}[/tex]
Step-by-step explanation:
Let X be the value of 3.2484848.... infinite times
Multiply by 100
[tex]x=3.24848....\\100x = 324.8484.....[/tex]
Subtract to get
[tex]100x-x = 324.8484...-3.248484....\\99x = 321.60\\x=\frac{321.6}{99} \\x=\frac{1072}{330} \\x=\frac{536}{165}[/tex]
Thus the number 3.248 repeating decimal with 48 repeating in fraction form is
[tex]\frac{536}{165}[/tex]
Answer:
[tex]\frac{536}{165}[/tex]
Step-by-step explanation:
Step 1: let's call [tex]x[/tex] the repeating decimal.
So, [tex]x=32.2484848484848...[/tex]
Step 2: identify the number of digits that repeats.
We see that two digits repeat 4 and 8.
Step 3: multiply 100 at each side of the equation, two digits, two zeros, that's why is 100.
[tex]100x=324.84848484848...[/tex]
Step 4: we subtract the repeating decimal the last expression:
[tex]100x-x=(324.8484848...)-(3.2484848...)\\99x=321.6[/tex]
Step 5: solve for [tex]x[/tex].
[tex]x=\frac{321.6}{99}[/tex]
In this case, we have to multiply each part of the fraction by 10 to get rid of the decimal number.
[tex]x=\frac{321.6(10)}{99(10)}=\frac{3216}{990}=\frac{536}{165}[/tex]
Therefore, the repeating decimal is equal to [tex]\frac{536}{165}[/tex]