Question

A motor with an operating resistance of 32 ohms is connected to a voltage source. the current in the circuit is 3.8
a. what is the voltage of the source?

Answer 1

V = I · R = (3.8 Amperes) · (32 ohms) = 121.6 volts

Answer 2

Considering the Ohm's law, the voltage of the source is 121.6 volts.

First of all, intensity (I) is the circulation of electrons that goes from one point to another. Its unit of measurement is amps.

On the other hand, the voltage (V) is the force that leaves the electrons that can have movement through the conductive material. Its unit of measurement is volts.

Finally, resistance (R) is the obstruction that is presented to electrons within a conduit, that is, it is the property of a material that limits the flow of current. Its unit of measurement is ohms.

The relationship between current, voltage, and resistance is expressed by Ohm's law. This law determines that the current flowing in a circuit is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit, provided that the temperature is kept constant.

Mathematically, Ohm's law is expressed as:

$I=\frac{V}{R}$

Or, expressed by another way:

V= I×R

In this case, you know:

• I= 3.8 A
• R=32 ohms

Replacing:

V=3.8 A× 32 ohms

Solving:

V= 121.6 volts

Finally, the voltage of the source is 121.6 volts.

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