Question

The force acting between two charged particles A and B is 5.2 * 10È¢ newtons. Charges A and B are 2.4 * 10ÈÆ meters apart. If the charge on particle A is 7.2 * 10ȧ coulombs, what is the charge of particle B? (k = 9.0 * 10© newton·metersÆ/coulombÆ)

Answer 1

The correct question is shown in the image attached with.

This is a question of Physics. Concept of Coulomb Force is used here. The formula for the Coulomb Force is:

$F=k \frac{ q_{1} q_{2} }{ r^{2} }$

F, k, r and $q_{1}$ are known and we are to find $q_{2}$ . Using the given values, we can write:

$5.2* 10^{-5}=9*10^{9}* \frac{7.2*10^{-8}* q_{2} }{(2,4 x 10^{-2} )^{2} }$

Simplifying and solving the equation for $q_{2}$ we get:

The charge of particle B = $q_{2}=4.6*10^{-11}$ Coulomb.