Respuesta :
The correct answer is d) 4x² - 4x + 1.
The area of a square is found by squaring the side length:
(2x-1)² = (2x-1)(2x-1) = 2x*2x - 2x*1 - 2x*1 - 1(-1) = 4x² - 2x - 2x + 1 = 4x²-4x+1
The area of a square is found by squaring the side length:
(2x-1)² = (2x-1)(2x-1) = 2x*2x - 2x*1 - 2x*1 - 1(-1) = 4x² - 2x - 2x + 1 = 4x²-4x+1
Answer: [tex]d. \ 4x^2-4x + 1[/tex]
Step-by-step explanation:
Given the length of one side of the square shaped traffic sign = (2x-1)
We need to find the expression for the area of the square shaped traffic sign.
Area of the square of given by formula
[tex]A= Side × Side [/tex]
Plugging value of expression length of side of the square in above formula, we get
A= (2x-1) (2x-1)
Let us foil it now.
A = (2x)(2x) +(2x)(-1) + (-1) (2x) +(-1)(-1)
= [tex]4x^2-2x-2x+1[/tex]
[tex]A=4x^2-4x+1[/tex]
Therefore, correct option is [tex]d. \ 4x^2-4x + 1[/tex]