Question

write the ratios for sin A and cos B. The triangle is not drawn to scale.

Answer 1

By definition we have:
 sineA = (C.O) / (h)
 cosA = (C.A) / (h)
 Where,
 C.O: opposite leg
 C.A: adjacent leg
  h: hypotenuse
 Substituting values:
 sinA = (48) / (50)
 cosA = (14) / (50)
 Answer:
 sineA = (48) / (50)
 cosA = (14) / (50) 
 Option 2

Answer 2

We want to find the ratios for Sin(A) and cos(A) for the given triangle, we will get:

• Sin(A) = 48/50
• Cos(A) = 14/50

Remember that in a right triangle we have the relations:

• Sin(θ) = (opposite cathetus)/(hypotenuse)
• Cos(θ) = (adjacent cathetus)/(hypotenuse).

With these relations is rather easy to find the ratios.

For the angle A, the opposite cathetus is the one of 48 units, and the hypotenuse is the side that measures 50 units, then:

Sin(A) = 48/50

For the angle A, the adjacent cathetus is the one that measures 14 units, then:

Cos(A) = 14/50

Then the correct option is the third one.

If you want to learn more about trigonometry, you can read:

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