Question

Manuel's division is shown.



Manuel did not write the remainder. What is the remainder over the divisor?

Answer 1

24 /a+3is the answer..................
HOPE IT HELPS YOU '_'

Answer 2

Answer:

$\frac{24}{a+3}$

Step-by-step explanation:

$Dividend = a^{2} -4a+3$

$Divisor =a+3$

Using long division method.

Dividend= (Divisor * Quotient)+Remainder

$a^{2} -4a+3=([a+3]*a)+(-7a+3)$

$a^{2} -4a+3=([a+3]*[a-7])+(24)$

Thus the remainder is 24

Since Manuel left the calculation : -7a+3-(-7a-21)= -7a+3+7a+21= 24

Solving his left calculation further we get the remainder 24.

Hence the remainder over divisor is $\frac{24}{a+3}$