Answer:
1 =d
2=a
3=f
4=b
5=e
6=c
Step-by-step explanation:
We are given a right angled triangle ABC
AB = c
BC = a
AC = b
Using Trigonometric ratio:
[tex]Sin\theta = \frac{Perpendicular}{Hypotenuse}[/tex]
[tex]Sin\theta = \frac{BC}{AB}[/tex]
For perpendicular BC base angle for sine is ∠A
So, [tex]Sin A = \frac{a}{c}[/tex]
So, 1 = d
Using Trigonometric ratio:
[tex]Sin\theta = \frac{Perpendicular}{Hypotenuse}[/tex]
[tex]Sin\theta = \frac{opposite}{Hypotenuse}[/tex] --1
[tex]Sin\theta = \frac{AC}{AB}[/tex]
For perpendicular AC base angle for sine is ∠B
So, [tex]Sin B = \frac{b}{c}[/tex]
So, 2 = a
Using 1
[tex]Sin\theta = \frac{opposite}{Hypotenuse}[/tex]
So, 3 = f
[tex]Cos \theta = \frac{Base}{Hypotenuse}[/tex]
[tex]Cos \theta = \frac{Adjacent}{Hypotenuse}[/tex]
So, 4 = b
Using Trigonometric ratio:
[tex]Tan\theta = \frac{Perpendicular}{Base}[/tex]
[tex]Tan\theta = \frac{BC}{AC}[/tex]
For Base AC base angle for Tan is ∠A
So, [tex]tan A = \frac{a}{b}[/tex]
So, 5 = e
Using Trigonometric ratio:
[tex]Tan\theta = \frac{Perpendicular}{Base}[/tex]
[tex]Tan \theta = \frac{AC}{BC}[/tex]
For Base BC base angle for Tan is ∠B
So, [tex]tan B = \frac{b}{a}[/tex]
So, 6 = c