Question

Solve x2 + 6x + 10 = 0 using the quadratic formula. what is the solution set?

Answer 1

Answer:

x = -3 + 1i and x = -3 - 1i

Step-by-step explanation:

With the problem: x² + 6x + 10 = 0

So using the formula: ax² + bx + c = 0

We narrow it to: a = 1, b = 6, c = 10

Discriminant: D = b² − 4ac (negative) or D = 36 − 40 = −4 (positive)

Formula: x= −b±√D / 2a

x= −6±√−4 / −2 = −3 ± i [i2=−1]

Therefore, your answer is:

x = -3 + 1i and x = -3 - 1i

(or x = -3 ± 1i)

*the "1" in front isn't necessary but it helps!*

Hope this helps!

- Shad -

Answer 2

We have that for the Question "Solve x2 + 6x + 10 = 0 using the quadratic formula. what is the solution set?" it can be said that the solution set is

• x=-3 + i
• x=-3 - i

From the question we are told

Solve x2 + 6x + 10 = 0 using the quadratic formula. what is the solution set?

Generally the equation for the quadratic formula  is mathematically given as

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\Therefore$

$x=\frac{-(6) \pm \sqrt{{6}^2-4*1*10}}{2*1}$

$x=\frac{-(6) \pm \sqrt{-4}}{2*1}\\\\x=-3 \pm i$

Therefore

the solution set is

x=-3 + i

x=-3 - i

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