Respuesta :
I guess this reads
[tex]\displaystyle\int_1^4f(x)\,\mathrm dx=19[/tex]
[tex]\displaystyle\int_1^4g(x)\,\mathrm dx=12[/tex]
You want to compute
[tex]I=\displaystyle\int_1^4(8f(x)-g(x)+7)\,\mathrm dx[/tex]
By linearity of the definite integral,
[tex]I=\displaystyle8\int_1^4f(x)\,\mathrm dx-\int_1^4g(x)\,\mathrm dx+7\int\mathrm dx[/tex]
[tex]I=8\cdot19-12+7(4-1)=\boxed{161}[/tex]
The value of the integral is 161.
We have
[tex]\int\limits^4_1 {f(x)} \, dx =19\\\int\limits^4_1 {g(x)} \, dx =12\\[/tex]
Now, the integral
[tex]\int\limits^4_1 {8f(x)-g(x)+7} \, dx \\=\int\limits^4_1 {8f(x)}dx-\int\limits^4_1g(x)+\int\limits^4_17} \, dx\\=8\int\limits^4_1 {f(x)}dx-\int\limits^4_1g(x)+7\int\limits^4_1} \, dx\\=8\times19-12+7(4-1)\\=8\times19-12+21\\=161[/tex]
The value of the integral [tex]\int\limits^4_1 {8f(x)-g(x)+7} \, dx[/tex] 161.
Therefore the correct option is 4.161
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