Find the three longest wavelengths (call them λ1, λ2, and λ3) that "fit" on the string, that is, those that satisfy the boundary conditions at x=0 and x=l. these longest wavelengths have the lowest frequencies. express the three wavelengths in terms of l. list them in decreasing order of length, separated by commas.

Respuesta :

If you have a string that is fixed on both ends the amplitude of the oscillation must be zero at the beginning and the end of the string. Take a look at the pictures I have attached. It is clear that  our fundamental harmonic will have the wavelength of:
[tex]\lambda_1=\frac{L}{2}[/tex]
All the higher harmonics are just multiples of the fundamental:
[tex]\lambda_n=n\lambda_1\\ \lambda_n=n\frac{L}{2} [/tex]
Three longest wavelengths are:
[tex]n=3; \lambda_3=\frac{3L}{2}\\ n=2; \lambda_2=L\\ n=1; \lambda_=\frac{L}{2}\\ [/tex]
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