Respuesta :
The probability of success is constant = p = 0.7
There are a fixed number of trials = n = 50
The trials are independent.
The sample is a simple random sample.
Thus, the given scenario satisfies all the conditions of a Binomial experiment so we will use Binomial probability to solve this problem.
We are to find the probability that greater than 30 bulbs will last atleast 8 hours.
So, we are to find P(X > 30)
We can use any Binomial calculator to find this value.
P(X> 30) comes out to be 0.9152
Therefore, the probability that greater than 30 batteries will last at least 8 hours is 0.9152.
There are a fixed number of trials = n = 50
The trials are independent.
The sample is a simple random sample.
Thus, the given scenario satisfies all the conditions of a Binomial experiment so we will use Binomial probability to solve this problem.
We are to find the probability that greater than 30 bulbs will last atleast 8 hours.
So, we are to find P(X > 30)
We can use any Binomial calculator to find this value.
P(X> 30) comes out to be 0.9152
Therefore, the probability that greater than 30 batteries will last at least 8 hours is 0.9152.
Answer:
0.9152
Step-by-step explanation:
Given that 50 identical batteries are being tested after 8 hours of continuous use.
Assumption is p = Probability for any bulb operating after 8 hours -=070
q= 0.30
n = number of trials = 50
X -- the no of bulbs which last more than 8 hours is binomial because
i) Each bulb is independent of the other
ii) There are only two outcomes, yes or no
Required probability = P(X>30)
=P(X=31)+P(X=31)+....+P(X=50)
=0.9159
=0.9152
Hence anwer is 0.9152
