The volume of the gas is [tex]V=0.923 L=0.923 \cdot 10^{-3} m^3[/tex]
The temperature of the gas is [tex]T=25^{\circ}C + 273 = 298 K[/tex]
Charle's law can be written as:
[tex] \frac{V}{T} =k[/tex]
So, by using the values of V and T, we can find the value of k, the Charle's law constant:
[tex] k=\frac{0.923 \cdot 10^{-3} m^3}{298 K}=3.10 \cdot 10^{-6} m^3 K^{-1} [/tex]
