carolinauribec2 carolinauribec2

29-03-2018
Mathematics

contestada

How many different arrangements of the letters A, D, G, and F are possible?

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evgeniylevi evgeniylevi

30-03-2018

Consider, pls, this option:
4!=1*2*3*4=24 different arrangements.
Explanation: it needed to use a formula A(n)=n!, where 'n' - number of letters.
If n=4, then 4!=24.

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