Question

two questions please help?

1. The figure shows the dimensions of a piece of scenery that will be painted to represent a mountain.
What is the area of this piece of scenery?
Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.

2. What is the area of △PQR
Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.

Answer 1

21.5, just took the test!!!!

Answer 2

Answer:

The area of triangle PQR is

$A=21.5\ cm^{2}$

Step-by-step explanation:

we know that

The area of a triangle is equal to

$A=\frac{1}{2}bh$

see the attached figure to better understand the problem

we have

$b=14\ cm$

$h=PS\ cm$

Find the length side of segment PS

In the right triangle PSR

$sin(20\°)=\frac{PS}{PR}$

Solve for PS

$PS=PRsin(20\°)$

we have

$PR=9\ cm$

substitute

$PS=(9)sin(20\°)$

Find the area of the triangle PQR

$A=\frac{1}{2}(14)((9)sin(20\°))$

$A=21.5\ cm^{2}$