Answer:
[tex]R=(\dfrac{b}{2},0)[/tex]
[tex]S=(\dfrac{b+c}{2},\dfrac{d}{2})[/tex]
[tex]T=(\dfrac{c+e}{2},\dfrac{d+f}{2})[/tex]
[tex]U=(\dfrac{e}{2},\dfrac{f}{2})[/tex]
[tex]M=(\dfrac{b+c+e}{4},\dfrac{d+f}{4})[/tex]
[tex]M=(\dfrac{c+b+e}{4},\dfrac{d+f}{4})[/tex]
Step-by-step explanation:
We are given coordinates as:
[tex]A(0,0)\ ,\ B=(b,0)\ ,\ C=(c,d)\ ,\ D=(e,f)\\\\R=(\dfrac{b}{2},0)\ ,\ S=(\dfrac{b+c}{2},\dfrac{d}{2})\ ,\ U=(\dfrac{e}{2},\dfrac{f}{2})\ ,\ T=(\dfrac{c+e}{2},\dfrac{d+f}{2})[/tex]
Now, it is given that M is the mid-point of the line segment RT and of US.
Hence, the coordinates of M is given as:
By taking the mid-point of side RT.
[tex]M=(\dfrac{\dfrac{b}{2}+\dfrac{c+e}{2}}{2},\dfrac{0+\dfrac{d+f}{2}}{2}})\\\\\\i.e.\\\\\\M=(\dfrac{b+c+e}{4},\dfrac{d+f}{4})[/tex]
By taking the mid-point of side US.
[tex]M=(\dfrac{\dfrac{e}{2}+\dfrac{b+c}{2}}{2},\dfrac{\dfrac{f}{2}+\dfrac{d}{2}}{2})\\\\\\i.e.\\\\\\M=(\dfrac{b+c+e}{4},\dfrac{d+f}{4})[/tex]