Respuesta :

[tex] \frac{4m-4n}{4m + 4n} = 0 [/tex]

Eventually 4m and 4n will cancel out because the above portion is a negative and the below is a positive. 
[tex] \dfrac{4m-4n}{4m+4n} [/tex]

Take out 4 as a common factor for both the numerator and the denominator:

[tex] = \dfrac{4(m-n)}{4(m+n)} [/tex]

[tex]= \dfrac{m-n}{m+n} [/tex]

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[tex]\bf \text { Answer = } \dfrac{m-n}{m+n} [/tex]
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