Respuesta :
Answer:
f(x)=4-4x ;
Domain:{0,1,3,5,6}
Range;{-20,-16,-8,0,4}
f(x)=5x-3
Domain:{-2,-1,0,3,4}
Range:{-13,-8,-3,12,4}
f(x)=-10x
Domain:{-4,-2,0,2,4}
Range:{-40,-20,0,20,40}
f(x)=[tex]\frac{3}{x}[/tex]+1.5
Domain:{-3,-2,-1,2,6}
Range:{0.5,0,-1.5,3,2}.
Step-by-step explanation:
First we take function f(x)=4-4x
Take Domain:{0,1,3,5,6}
If, we take x=0 and put in the function then we get
f(x)=[tex]4-4\times0[/tex]
f(x)=4-0
f(x)=4
put x=1
then f(x)=[tex]4-4\times1[/tex]
f(x)=4-4=0
put x=3 then we get
f(x)=4-12=--8
put x=5 them we get
f(x)=4-20=-16
put x=6 then we get
f(x)=4-24=-20
Therefore ,range:[-20,-16,-8,0,4}
Now ,we take function f(x)=5x-3
Take domain{-2,-1,0,3,4}
Now, put x=-2 in the function then we get
f(x)=[tex]5\times(-2)-3[/tex]
f(x)=-13
now put x=-1 then we get
f(x)=-5-3=-8
Put x=0 then we get
f(x)=0-3=-3
Put x=3 then we get
f(x)=15-3=12
Put x=4 then we get
f(x)=20-3=17
Therefore , range:{-13,-8,-3,12,17}
Now, we take III function f(x)=-10x
Take domain:{-4,-2,0,2,4}
Put x=-4 in the function then we get
f(x)=[tex]10\times[tex]10\times(-4)[/tex]
f(x)=-40
Put x= -2 then we get
f(x)=[tex]10\times(-2)=-20[/tex]
Put x=0 then we get
f(x)=0
Put x=2 then we get
f(x)=20
Put x=4 then we get
f(x)=40
Therefore , range :{-40,-20,0,20,40}
Now, we take IV function f(x)=[tex]\frac{3}{x}[/tex]+1.5
Take domain:{-3,-2,-1,2,6}
Put x= -3 in the taken function then we get
f(x)=-1+1.5=0.5
put x=-2 then we get
f(x)= -1.5+1.5=0
Put x=-1 then we get
f(x)=-3+1.5=-1.5
Put x= 2 then we get
f(x)=1.5+1.5=3
Put x= 6 then we get
f(x)=0.5+1.5=2
Therefore, range : {0.5,0,-1.5,3,2}.