A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. Which equation should be used to calculate the diver’s kinetic energy?

Respuesta :

The Kinetic energy formula will be used:

Ek= 1/2mv^2

Ek= 1/2x72x79^2

Ek= 224,676 Joules

The correct equation to use to calculate the kinetic energy of an object is:

[tex] K=\frac{1}{2}mv^2 [/tex]

where

m is the mass of the object

v is its speed


In this problem, the mass of the skydiver is [tex] m=72.0 kg [/tex], while its speed is [tex] v=79.0 m/s [/tex], therefore his kinetic energy is

[tex] K=\frac{1}{2}(72.0 kg)(79.0 m/s)^2=2.25 \cdot 10^5 J [/tex]

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