Question

A balloon is filled with 5 moles of helium gas. At a pressure of 1.18 atm and a temperature of 303 K, what volume will the gas occupy?

Answer 1

ideal gas law: p·V = n·R·T.
p - pressure of gas; p = 1,18 atm · 101,325 kPa/atm = 119,56 kPa.
V -volume of gas.
n - amount of substance, n(He) = 5 mol.
R - universal gas constant; R = 8,314 J/K·mol .
T - temperature of gas; T(He) = 303 K.
From formula of ideal gas law: V = n·R·T / p.
V(He) = 5 mol · 8,314 J/K·mol · 303 K ÷ 119,56 kPa.
V(He) = 105,35 dm³ = 105,35 L.