Question

Find the values of y = r(x) = ∛x for
x = –2.197, –1.331, 0, 1.331, 2.197, 3.375, 4.913
Then plot the corresponding points on a graph.

Answer 1

We're being asked to find the values of y for $\sqrt[3]{x}$ for specific values of x. Basically, we are taking the cube roots of these numbers.



$r(-2.197) = \sqrt[3]{-2.197} = -1.3\\\\ r(-1.331) = \sqrt[3]{-1.331} = -1.1\\\\ r(0) = \sqrt[3]{0} = 0 \\\\ r(1.331) = \sqrt[3]{1.331} = 1.1\\\\r(2.197) = \sqrt[3]{2.197} = 1.3\\\\r(-3.375) = \sqrt[3]{-3.375} = 1.5\\\\r(4.913) = \sqrt[3]{4.913} = 1.7$

Answer 2

Answer:

Step-by-step explanation:

For a given function r(x) = y = ∛x

We have to fined the points on the given curve and then we will plot the points on a graph.

y = ∛x

For x = -2.197

y = ∛(-2.197) = -1.30

For x = -1.331

y = ∛(-1.331) = -1.1

For x = 0

y = ∛0 = 0

For x = 1.331

y = ∛1.331 = 1.1

For x = 2.197

y = ∛2.197 = 1.30

For x = 4.913

y =∛4.913 =1.70

So the points are (-2.197, -1.30), (-1.331, -1.1), (0, 0), (1.331, 1.1), (2.197, 1.30), (4.913, 1.70)

Now we plot the points on a graph.