Respuesta :
the complete question in the attached figure
we know that
radius r of a circle=4 units
in the triangle OST
OT=OS=4 units
m∠OST = 60°
cos 60°=(ST/2)/r-------> ST=2*r*cos 60°-----> 2*4*(1/2)----> 4 units
so
triangle OST
it's an equilateral triangle
the answer Part a) is
ST=4 units
Part b)
Find PT
in the triangle POT
m∠POT = (180°-60°)---------> 120°
m∠OTP = 30°
cos 30°=(PT/2)/r------> PT=2*r*cos 30°------> 2*4*√3/2----> 4√3 units
the answer Part b) is
PT=4√3 units
we know that
radius r of a circle=4 units
in the triangle OST
OT=OS=4 units
m∠OST = 60°
cos 60°=(ST/2)/r-------> ST=2*r*cos 60°-----> 2*4*(1/2)----> 4 units
so
triangle OST
it's an equilateral triangle
the answer Part a) is
ST=4 units
Part b)
Find PT
in the triangle POT
m∠POT = (180°-60°)---------> 120°
m∠OTP = 30°
cos 30°=(PT/2)/r------> PT=2*r*cos 30°------> 2*4*√3/2----> 4√3 units
the answer Part b) is
PT=4√3 units

Answer:
pt=[tex]8\sqrt{3[/tex]
st=4
Step-by-step explanation:
ha;f of pt is 4sqrt 3
and st is given by r which is 4
find pt htrough 30-60-90