Which system of linear inequalities is represented by the graph? y > x + 3 and 3x – y > 2 y > x + 3 and 3x – y > 2 y > x + 3 and 3x + y > 2 y > x + 3 and 2x – y > 2

The lines represent the inequalities [tex]\boxed{y>\frac{1}{3}x + 3{\text{ and }}3x - y > 2.}[/tex] .
Further explanation:
The linear equation with slope m and intercept c is given as follows.
[tex]\boxed{y = mx + c}[/tex]
The formula for slope of line with points [tex]\left( {{x_1},{y_1}}\right)[/tex] and [tex]\left( {{x_2},{y_2}}\right)[/tex] can be expressed as,
[tex]\boxed{m=\dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}}[/tex]
Given:
The inequalities are as follows.
a. [tex]y > x + 3{\text{ and }}3x - y > 2[/tex]
b.[tex]y > x + 3{\text{ and }}3x - y > 2[/tex]
c.[tex]y > x + 3{\text{ and }}3x + y > 2[/tex]
d.[tex]y > x + 3{\text{ and 2}}x - y > 2[/tex]
Explanation:
The blue line intersects y-axis at [tex](0, - 2)[/tex], therefore the y-intercept is .
The blue line intersect the points that are [tex]\left( {1,1} \right)[/tex] and [tex]\left( {0, - 2}\right)[/tex].
The slope of the line can be obtained as follows.
[tex]\begin{aligned}m&=\frac{{1 -\left({- 2} \right)}}{{1 - 0}}\\&=\frac{{1 + 2}}{1}\\&=3\\\end{aligned}[/tex]
The slope of the line is [tex]m = 3[/tex].
Now check whether the inequality included origin or not.
Substitute [tex]\left( {0,0}\right)[/tex] in equation [tex]y < 3x - 2[/tex].
[tex]\begin{aligned}\left( 0 \right) &< 3\left( 0 \right)- 2\\0 &< - 2\\\end{aligned}[/tex]
0 is not less than which mean that the inequality doesn’t include origin.
Therefore, the blue line is [tex]y < 3x--2{\text{ or }}3x - y > 2[/tex].
The orange line intersects y-axis at [tex]\left( {0,3}\right)[/tex], therefore the y-intercept is 3.
The orange line intersect the points that are [tex]\left( { - 3,2}\right)[/tex] and [tex]\left( {0,3}\right)[/tex].
The slope of the line can be obtained as follows.
[tex]\begin{aligned}m&=\frac{{3 - 2}}{{0 - \left( { - 3}\right)}}\\&=\frac{1}{3}\\\end{aligned}[/tex]
The slope of the line is [tex]m = \dfrac{1}{3}[/tex].
Now check whether the inequality included origin or not.
Substitute [tex]\left( {0,0}\right)[/tex] in equation [tex]y > \dfrac{1}{3}\left( x \right) + 3[/tex].
[tex]\begin{aligned}\left(0 \right)&>\frac{1}{3}\left(0\right) + 3\\0&>3\\\end{aligned}[/tex]
0 is not greater than 3 which mean that the inequality doesn’t include origin.
Therefore, the orange line is [tex]y > \dfrac{1}{3}x + 3[/tex].
The lines represent the inequalities [tex]\boxed{y > \frac{1}{3}x + 3{\text{ and }}3x - y > 2.}[/tex].
Learn more:
1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
2. Learn more about equation of circle brainly.com/question/1506955.
3. Learn more about range and domain of the function https://brainly.com/question/3412497
Answer details:
Grade: High School
Subject: Mathematics
Chapter: Linear inequalities
Keywords: numbers, slope, slope intercept, inequality, equation, linear inequality, shaded region, y-intercept, graph, representation, origin.