Respuesta :
Refer to https://brainly.com/question/9480049
The lengths of the sides of the triangle are 16, 63, and 65.
a0 = 63
a1 = 65
_____
You have
.. a0² +16² = a1²
You want
.. a1 = a0 +2
so
.. a0² +256 = (a0 +2)² = a0² +4a0 +4 . . . . substitute and expand
.. 252 = 4a0 . . . . . . . . . subtract a0² +4
.. 63 = a0 . . . . . . . . . . . .divide by 4
.. a1 = 63 +2 = 65
The lengths of the sides of the triangle are 16, 63, and 65.
a0 = 63
a1 = 65
_____
You have
.. a0² +16² = a1²
You want
.. a1 = a0 +2
so
.. a0² +256 = (a0 +2)² = a0² +4a0 +4 . . . . substitute and expand
.. 252 = 4a0 . . . . . . . . . subtract a0² +4
.. 63 = a0 . . . . . . . . . . . .divide by 4
.. a1 = 63 +2 = 65
Answer:
All sides are : 16,63,65 units
Step-by-step explanation:
Let the other leg be = x
So, hypotenuse will be = x+2
And one leg is = 16
So, Pythagoras theorem is :
[tex]a^{2} +b^{2}=c^{2}[/tex] , where c is hypotenuse.
Now we can calculate this as:
[tex]16^{2} +x^{2} =(x+2)^{2}[/tex]
=> [tex]256+x^{2} =x^{2} +4x+4[/tex]
Clubbing the like terms together;
=> [tex]x^{2} -x^{2} -4x=-256+4[/tex]
[tex]-4x=-252[/tex]
x = 63
So, hypotenuse is = [tex]63+2=65[/tex] units
Therefore, all the lengths are = 16,63 and 65 units.