Respuesta :

A sum of a finite number of numbers must be convergent.

Consider the [tex]k[/tex]-th partial sum for the series:

[tex]S_k=\displaystyle\sum_{n=2}^k(-3)\cdot4^{n-1}[/tex]
[tex]S_k=-3(4^1+4^2+\cdots+4^{k-2}+4^{k-1})[/tex]
[tex]4S_k=-3(4^2+4^3+\cdots+4^{k-1}+4^k)[/tex]
[tex]\implies S_k-4S_k=-3(4^1-4^k)[/tex]
[tex]\implies S_k=4(1-4^{k-1})[/tex]

In this case, we have [tex]k=5[/tex], so the sum we want to find is

[tex]S_5=4(1-4^{5-1})=-1020[/tex]
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