Respuesta :
Balance the equation first:
1C4H10 + 13O2 ----> 8CO2 + 10H2O
As we know oxygen is in excess, butane is the limiting reactant.
the ratio between butane and CO2 is 1-8
Therfore
1:8
6:x
x=48
48 moles of CO2 will be produced
1C4H10 + 13O2 ----> 8CO2 + 10H2O
As we know oxygen is in excess, butane is the limiting reactant.
the ratio between butane and CO2 is 1-8
Therfore
1:8
6:x
x=48
48 moles of CO2 will be produced
Answer: 24 moles
Explanation:
Combustion is a type of chemical reaction in which hydrocarbon is oxidized to carbon dioxide and water.
The balanced chemical reaction for combustion of butane is :
[tex]2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O[/tex]
According to stoichiometry,
Given: Oxygen is the excess reagent. Thus butane is the limiting reagent as it limits the formation of product.
2 moles of butane gives 8 moles of carbon dioxide.
Thus 6 moles of butane will give=[tex]\frac{8}{2}\times 6=24moles[/tex] of carbon dioxide.
