Which expression is equivalent to square root 128x^8y^3z^9? Assume y>0 and z>o

Answer:
Option (3) is correct.
The given expression [tex]\sqrt{128x^8y^3z^9}[/tex] becomes [tex]8x^4yz^4\sqrt{2yz}[/tex]
Step-by-step explanation:
Given : Expression [tex]\sqrt{128x^8y^3z^9}[/tex]
We have to choose an equivalent expression to the given expression [tex]\sqrt{128x^8y^3z^9}[/tex] and choose the correct from the given options.
Consider the given expression [tex]\sqrt{128x^8y^3z^9}[/tex]
128 can be written as prime factors as 2 × 2 × 2 × 2 × 2 × 2 × 2 = [tex]2^7[/tex]
Thus, [tex]\sqrt{128}=\sqrt{2^7}=\sqrt{2^6\cdot 2}=2^3\sqrt{2}=8\sqrt{2}[/tex]
also, [tex]\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0[/tex]
[tex]\sqrt{x^8}=x^{\frac{8}{2}}[/tex]
Similarly, [tex]\sqrt{y^3}=\sqrt{y^2\cdot y}=y\sqrt{y}\\\\ \sqrt{z^8}=\sqrt{z^8\cdot z}=z^4\sqrt{z}[/tex]
Thus, The given expression [tex]\sqrt{128x^8y^3z^9}[/tex] becomes [tex]8x^4yz^4\sqrt{2yz}[/tex]