Respuesta :

It is d because 64 x2 =128

Answer:

Option (3) is correct.

The given expression [tex]\sqrt{128x^8y^3z^9}[/tex]  becomes [tex]8x^4yz^4\sqrt{2yz}[/tex]

Step-by-step explanation:

Given : Expression [tex]\sqrt{128x^8y^3z^9}[/tex]

We have to choose an equivalent expression to the given expression [tex]\sqrt{128x^8y^3z^9}[/tex] and choose the correct from the given options.

Consider the given expression  [tex]\sqrt{128x^8y^3z^9}[/tex]

128 can be written as prime factors as 2 × 2 × 2 × 2 × 2 × 2 × 2 = [tex]2^7[/tex]

Thus, [tex]\sqrt{128}=\sqrt{2^7}=\sqrt{2^6\cdot 2}=2^3\sqrt{2}=8\sqrt{2}[/tex]

also, [tex]\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0[/tex]

[tex]\sqrt{x^8}=x^{\frac{8}{2}}[/tex]

Similarly, [tex]\sqrt{y^3}=\sqrt{y^2\cdot y}=y\sqrt{y}\\\\ \sqrt{z^8}=\sqrt{z^8\cdot z}=z^4\sqrt{z}[/tex]

Thus, The given expression [tex]\sqrt{128x^8y^3z^9}[/tex]  becomes [tex]8x^4yz^4\sqrt{2yz}[/tex]

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