Question

What is the gravitational force fgrav on the satellite? take the gravitational constant to be g = 6.67×10−11 n⋅m2/kg2 , the mass of the earth to be me = 5.97×1024 kg , and the radius of the earth to be re = 6.38×106 m ?

Answer 1

The gravitational force on the satellite is approximately equal to 16,757 N

Answer 2

The question is incomplete, complete question is:

A satellite used in a cellular telephone network has a mass of 2500 kg and is in a circular orbit at a height of 700 km above the surface of the earth.

What is the gravitational force on the satellite?

Take the gravitational constant to be $G = 6.67\times 10^{-11} Nm^2/kg^2$ , the mass of the earth to be $m_e = 5.97\times 10^{24} kg$ , and the radius of the Earth to be $r_e = 6.38\times 10^6 m$

Answer:

19,859.74 Newtons is the gravitational force on the satellite.

Explanation:

Mass of the satellite = $m=2500 kg$

Mass of earth = $m_e=5.97\times 10^{24} kg$

Distance between satellite and earth, d = $r_e+700 km=6.38\times 10^6 m+700,000 m=7.08\times 10^6 m$

Gravitational constant = $G= 6.67\times 10^{-11} Nm^2/kg^2$

$F=G\times \frac{m\times m_e}{d^2}$

$F=6.67\times 10^{-11} Nm^2/kg^2\times \frac{2500 kg\times 5.97\times 10^{24} kg}{(7.08\times 10^6 m)^2}$

$F=19,859.74 N$

19,859.74 Newtons is the gravitational force on the satellite.