Question

What is the distance between points A(3, 12) and B(6, 15)? Round to the nearest whole number.

Answer 1

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:

$\mathsf{d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}}$

"d" represents the distance and coordinates are expressed as follows: (x, y)

Let's go to the calculations.

$\mathsf{d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}}\\\\ \mathsf{d=\sqrt{(6-3)^2+(15-12)^2}}\\\\ \mathsf{d=\sqrt{(3)^2+(3)^2}}\\\\ \mathsf{d=\sqrt{9+9}}\\\\ \mathsf{d=\sqrt{18}}\\\\ \mathsf{d=4,24264068711928514640...}\\\\ \underline{\mathsf{d\approxeq4}}$

The answer is 4 u.c.

Answer 2

The distance between points A(3, 12) and B(6, 15) rounded to the nearest whole number is; d_ab = 4

The formula for distance between two coordinates points is;

d = √[(x2 - x1)² + (y2 - y1)²]

We are given the coordinates A(3, 12) and B(6, 15)

Thus;

x1 = 3

x2 = 6

y1 = 12

y2 = 15

Therefore;

d_ab = √[(6 - 3)² + (15 - 12)²]

d_ab = √(3² + 3²)

d_ab = 4.243

Approximating to the nearest whole number gives;

d_ab = 4

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