Question

find point-slope.

(3/2, -1/2)
(-2/3, 1/3)

x1: 3/2
x2: -2/3
y1: -1/2
y2: 1/3

to find slope:
m= y2-y1/x2-x1

point-slope:
y-y1=m(x-x1)

Answer 1

this iis easie guise, why don't you do it? so
point slope=y-y1=m(x-x1)

so just subsitute
first find m
m=(y2-y1)/(x2-x1)=(1/3-(-1/2))/(-2/3-3/2)=(1/3+1/2)/(-2/3-3/2)=(5/6)/(-13/6)=-5/13
m=-5/13
subsitute
y-y1=-5/13(x-x1)
subsitute
y-(-1/2)=-5/13(x-3/2)
y+1/2=-5/13x+15/26
subtract 1/2 from both sides
y=-5/13x+15/26-13/26 (1/2=13/26)
y=-5/13x+2/26
y=-5/13x+1/13

Answer 2

Answer:

Step-by-step explanation:

Sample Answer:When a linear function is expressed in different forms, its slope and y-intercept remain the same. The slope from the equation is -1, and the y-intercept from the equation is 3. The slope from the table is -1, and the y-intercept from the table is −3. These are not the same functions.

hope this helps.