Question

If xy + 2ey = 2e, find the value of y'' at the point where x = 0.

Answer 1

Answer:

y = 1 is the value at x = 0

Step-by-step explanation:

The given equation is xy + 2ey = 2e

We have to solve this equation to find the value of y at the point x = 0.

xy + 2ey = 2e

y(x + 2e) = 2e

Now we divide this equation by (x + 2e) on both the sides of the equation.

$y=\frac{2e}{(x+2e)}$

Now we have find the value of y at x = 0

By putting x = 0 in the simplified form of the equation

$y=\frac{2e}{(0+2e)}=\frac{2e}{2e}=1$

So the value of y is 1.

Answer 2

At $x=0$ the value of $y$ is $\boxed{y=1}$.

Further explanation:

The value of $y$ coordinate can be calculated by the substitution method.

Procedure:

The following steps are involved to find the $y$ coordinate for any linear equation.

1) Make factors of the equation if possible.

2) Write the given equation in terms of $y$.

3) Substitute the $x$ coordinate in the obtained equation to find the value of $y$.

Given:

The linear equation in two variables is $xy+2ey=2e$ and the $x$ coordinate is $0$.

Step 1:

Make factors for the equation $xy+2ey=2e$.

$\begin{aligned}xy+2ey&=2e\\y(x+2e)&=2e\end{aligned}$

Step 2:

Now write the equation in terms of $y$ as,

$y=\dfrac{2e}{x+2e}$

Step 3:

Now we have to find $y$ coordinate at the point $x=0$ of the equation $xy+2ey=2e$.

Substitute $x=0$ in the equation $y=\frac{2e}{x+2e}$ to obtain the value of $y$.

$\begin{aligned}y&=\dfrac{2e}{x+2e}\\&=\dfrac{2e}{0+2e}\\&=\dfrac{2e}{2e}\\&=1\end{aligned}$  

Therefore, at $x=0$ the value of $y$ is $\boxed{y=1}$.

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Linear equation in two variables

Keywords:  Linear equations, linear form, equation, line, slope, intercept, coordinate, solutions set, degree, polynomial, variable, point, constant.