Since we are given the voltage over the capacitor, current will be (because resistor and capacitor are in series the current flowing through them has to be the same):
[tex]I=\frac{V_{C0}}{Z_C}[/tex]
Where Zc is the impedance of the capacitor. The impedance of the capacitor is:
[tex]Z_C=\frac{1}{Cw}[/tex]
When we plug that back into the first formula we get:
[tex]I=\frac{V_{C0}}{1/Cw}=V_{C0}Cw[/tex]