Question

What is the axis of symmetry of h(x)=5x^2+40x+64

Answer 1

For ax^2 +bx +c, the axis of symmetry is given by
.. x = -b/(2a)

You have
.. a = 5
.. b = 40
so the axis of symmetry is
.. x = -40/(2*5)
.. x = -4

Answer 2

Answer:

2

Step-by-step explanation:

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