Question

The standard form of the equation of a circle is (x−3)^2+(y−1)^2=16.
What is the general form of the equation?

A- x^2+y^2−6x−2y−6=0

B- x^2+y^2−6x−2y−26=0

C- x^2+y^2+6x+2y+26=0

D- x^2+y^2+6x+2y−6=0

Answer 1

so the answer is A.......