Question

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Answer 1

at STP 1 mol of any gas has volume =22.4 L
25L*1mol/22.4L=1.12 mol
Answer is 1.12 mol

Answer 2

Given volume of hydrogen = 25 L

Standard temperature = 273 K

Standard pressure = 1 atm

R is gas constant = 0.08206 L.atm/(mol.K)

Plugging in the values in ideal gas equation and solving for moles of hydrogen (n):

$PV = nRT$

$1 atm (25 L) = n (0.08206 L.atm/(mol.K))(273 K)$

$n = \frac{(1atm)(25 L)}{(0.08206 L.atm/(mol.K))(273 K)}$

n = 1.12 mol