Respuesta :
the balanced equation for combustion of octane is given below
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
stoichiometry of octane to carbon dioxide is 2:16
number of moles of octane burnt - 1700 g / 114.2 g/mol = 14.88 mol
For every 2 mol of octane - 16 mol of CO₂ is formed
Therefore for 14.88 mol of octane - 16/2 x 14.88 mol = 119.0 mol of CO₂
Mass of CO₂ formed - 119.0 mol x 44 g/mol = 5236 g
mass of CO₂ formed - 5.236 kg
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
stoichiometry of octane to carbon dioxide is 2:16
number of moles of octane burnt - 1700 g / 114.2 g/mol = 14.88 mol
For every 2 mol of octane - 16 mol of CO₂ is formed
Therefore for 14.88 mol of octane - 16/2 x 14.88 mol = 119.0 mol of CO₂
Mass of CO₂ formed - 119.0 mol x 44 g/mol = 5236 g
mass of CO₂ formed - 5.236 kg
The mass of carbon dioxide that is added to the atmosphere per 1.7 kg of octane burned is 5.236 kg
What is a combustion reaction?
A combustion reaction is one in which the substance reacts with oxygen to produce heat and light.
The combustion reaction is
2C₈H₁₈ + 25O₂ = 16CO₂ + 18H₂O
By stoichiometry
octane : carbon dioxide
2: 16
Calculating the number of moles
[tex]\rm Number\;of \;moles= \dfrac{mass}{molar\;mass}\\\\\rm Number\;of \;moles= \dfrac{1700 g }{114.2 g/mol}= 14.48\;mol[/tex]
Now, according to stoichiometry,
The 14.48 moles of octane will be
[tex]\dfrac{6}{2}\times 14.88 mol = 119.0\; mol\; of\; CO_2[/tex]
Mass of carbon dioxide will be
119.0 mol × 44 g/mol = 5236 g
Thus, the mass of carbon dioxide is 5.236 kg
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