a. The net torque on the 2.0-m-long uniform beam about point C is 14 Nm anticlockwise
b. The net torque on the 2.0-m-long uniform beam about point P is 13 Nm clockwise
Further explanation
Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
[tex]\large {\boxed {F = ma }[/tex]
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
This problem is about moment of force!
Given:
F₁ = 56 N
θ₁ = 32°
F₂ = 65 N
θ₂ = 45°
F₃ = 52 N
θ₃ = 58°
Unknown:
τ = ?
Solution:
About Point C:
[tex]\Sigma \tau_C = F_1d_1 \sin \theta_1 + F_2d_2 \sin \theta_2 + F_3d_3 \sin \theta_3[/tex]
[tex]\Sigma \tau_C = 56(1) \sin 32^o + 65(0) \sin 45^o - 52(1) \sin 58^o[/tex]
[tex]\Sigma \tau_C = 29.675 + 0 - 44.099[/tex]
[tex]\Sigma \tau_C \approx -14 \texttt{ Nm}[/tex] ( anticlockwise )
[tex]\texttt{ }[/tex]
About Point P:
[tex]\Sigma \tau_P = F_1d_1 \sin \theta_1 + F_2d_2 \sin \theta_2 + F_3d_3 \sin \theta_3[/tex]
[tex]\Sigma \tau_P = 56(2) \sin 32^o - 65(1) \sin 45^o + 52(0) \sin 58^o[/tex]
[tex]\Sigma \tau_P = 59.351 - 45.962 - 0[/tex]
[tex]\Sigma \tau_P \approx 13 \texttt{ Nm}[/tex] ( clockwise )
[tex]\texttt{ }[/tex]
Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
- Newton's Law of Motion: https://brainly.com/question/10431582
- Example of Newton's Law: https://brainly.com/question/498822
Answer details
Grade: High School
Subject: Physics
Chapter: Dynamics
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
