Question

What is the area of the isosceles trapezoid shown?

Answer 1

Area of a trapezoid is the average of the bases times the height. (9+4.5)/2 = 13.5/2 = 6.75. 6.75 is the average of the bases you have to multiply that number by the height so 6.75x6= 40.5cm squared. The correct answer is C.

Answer 2

Answer: C. $40.5\ cm^2$

Step-by-step explanation:

The area of a trapezoid is given by :-

$A=\dfrac{1}{2}h(a+b)$, where a and b are the lengths of the opposite parallel sides and h is height.

From the given figure , we have an isosceles trapezoid with

a= 4.5 cm  ;  b= 9 cm and h = 6 cm.

Then, the area of the isosceles trapezoid will be :-

$A=\dfrac{1}{2}(6)(4.5+9)\\\\=(3)(13.5)=40.5\ cm^2$

Hence, the  area of the isosceles trapezoid = $40.5\ cm^2$