A plane flies with a velocity of 52m/s east through a 12 m/s cross wind blowing from the north. Find the resultant velocity

Respuesta :

From a bird's eye view, the plane will be flying northeast.  The velocity in the direction of flight will be slightly more than 52m/s; it will be the length of the hypotenuse of the right triangle formed by it's east and north velocities.

Its east velocity is 52m/s and its north velocity is 12m/s so its velocity from a bird's eye view is (by the Pythagorean theorem)[tex]\sqrt{52^2+12^2}=\sqrt{2848}=4\sqrt{178}\approx 53.366\text{ m/s}[/tex]
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