anialewandowki anialewandowki

27-03-2018
Chemistry

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determine the mass of solute required to form 275mL of a 0.42M KClO3 solution

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popalabdulqayou popalabdulqayou

27-03-2018

Molarity= moles/litres
.42M=x moles/.275litres
xmoles=.42M*.275litres= .1155 moles
molar mass of KClO3 = 122.548 grams/moles
mass= 122.548grams/moles* .1155moles= 14.15 grams of PotassiumClorate.\Hopes this loves or thanks.

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